Question:

Identify A, B, and C in the given reaction sequence: \[ \text{A} \xrightarrow{\text{HNO}_3} \text{Pb(NO}_3)_2 \xrightarrow{\text{H}_2\text{SO}_4} \text{B} \rightarrow \text{C (Yellow ppt)}. \]

Show Hint

The reaction sequence involves the formation of lead nitrate, lead sulfate, and lead chromate. This is a typical sequence for testing the presence of lead in reactions with chromates.
Updated On: Mar 17, 2025
  • Ammonium acetate
  • Acetic acid
  • \( \text{K}_2\text{CrO}_4 \)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Step 1 (A): When lead (Pb) reacts with nitric acid (\( \text{HNO}_3 \)), lead nitrate (\( \text{Pb(NO}_3)_2 \)) is formed: \[ \text{Pb} + 2 \text{HNO}_3 \rightarrow \text{Pb(NO}_3)_2 + \text{H}_2. \] - Step 2 (B): When lead nitrate reacts with sulfuric acid (\( \text{H}_2\text{SO}_4 \)), lead sulfate (\( \text{PbSO}_4 \)) is formed: \[ \text{Pb(NO}_3)_2 + \text{H}_2\text{SO}_4 \rightarrow \text{PbSO}_4 + 2 \text{HNO}_3. \] - Step 3 (C): When lead sulfate (\( \text{PbSO}_4 \)) reacts with potassium chromate (\( \text{K}_2\text{CrO}_4 \)), a yellow precipitate of lead chromate (\( \text{PbCrO}_4 \)) is formed: \[ \text{PbSO}_4 + \text{K}_2\text{CrO}_4 \rightarrow \text{PbCrO}_4 (yellow ppt) + \text{K}_2\text{SO}_4. \] Thus, A is Pb, B is PbSO₄, and C is PbCrO₄ (yellow ppt).
Was this answer helpful?
0
0

Top Questions on Chemical Reactions

View More Questions

Questions Asked in JEE Main exam

View More Questions