Step 1: Elements and subsets.
The set has 6 elements: \(\{1,2,3,4,5,6\}\).
Number of subsets = \(2^6 = 64\).
Step 2: Condition \(S \subseteq T\).
For each element, there are 3 possibilities:
1. The element is in \(T\) but not in \(S\).
2. The element is in both \(S\) and \(T\).
3. The element is in neither \(S\) nor \(T\).
Thus, each element has 3 valid choices.
Step 3: Total number of pairs.
\[
\text{Total pairs} = 3^6 = 729
\]
\[
\boxed{729}
\]
Let R = {(1, 2), (2, 3), (3, 3)}} be a relation defined on the set \( \{1, 2, 3, 4\} \). Then the minimum number of elements needed to be added in \( R \) so that \( R \) becomes an equivalence relation, is:
P and Q play chess frequently against each other. Of these matches, P has won 80% of the matches, drawn 15% of the matches, and lost 5% of the matches.
If they play 3 more matches, what is the probability of P winning exactly 2 of these 3 matches?