Step 1: Analyze the positions of cars at 11:00 AM.
Car P travels at 25 km/h for 1.5 hours (from 10 AM to 11:30 AM), so the distance traveled by car P is: \[ \text{Distance of car P} = 25 \times 1.5 = 37.5 \, \text{km}. \] Car Q travels at 30 km/h for 1 hour, so the distance covered by car Q in the first hour is: \[ \text{Distance of car Q in 1 hour} = 30 \times 1 = 30 \, \text{km}. \] Step 2: Use the Pythagorean theorem.
Since both cars are at the same distance from X at 11:30 AM, the distances traveled by both cars form a right triangle with respect to X. For car Q to meet car P at the same distance, we calculate the missing distance using the Pythagorean theorem: \[ \text{Distance of car Q at 11:30 AM} = \sqrt{(30^2 + 37.5^2)} \approx 47.43 \, \text{km}. \] Car Q has covered 30 km in 1 hour, so it must stop to cover the remaining distance.
Step 3: Calculate the time Q stopped.
Car Q needs to travel \( 47.43 - 30 = 17.43 \, \text{km} \). At a speed of 30 km/h, the time taken to travel this distance is: \[ \text{Time taken to travel remaining distance} = \frac{17.43}{30} \times 60 = 34.86 \, \text{minutes}. \] Thus, car Q must have stopped for approximately \( 34.86 - 15 = 15 \) minutes.
Identify the option that has the most appropriate sequence such that a coherent paragraph is formed:
Statement:
P. At once, without thinking much, people rushed towards the city in hordes with the sole aim of grabbing as much gold as they could.
Q. However, little did they realize about the impending hardships they would have to face on their way to the city: miles of mud, unfriendly forests, hungry beasts, and inimical local lords—all of which would reduce their chances of getting gold to almost zero.
R. All of them thought that easily they could lay their hands on gold and become wealthy overnight.
S. About a hundred years ago, the news that gold had been discovered in Kolar spread like wildfire and the whole State was in raptures.
For a hydrocarbon reservoir, the following parameters are used in the general material balance equation (MBE):
\[ \begin{aligned} N & = \text{Initial (original) oil in place, stb} \\ G & = \text{Initial volume of gas cap, scf} \\ m & = \text{Ratio of initial volume of gas cap to volume of oil initial in place, rb/rb} \\ S_{wi} & = \text{Initial water saturation} \\ S_{oi} & = \text{Initial oil saturation} \\ B_{oi} & = \text{Initial oil formation volume factor, rb/stb} \\ B_{gi} & = \text{Initial gas formation volume factor, rb/scf} \end{aligned} \]
The total pore volume (in rb) of the reservoir is:
A stationary tank is cylindrical in shape with two hemispherical ends and is horizontal, as shown in the figure. \(R\) is the radius of the cylinder as well as of the hemispherical ends. The tank is half filled with an oil of density \(\rho\) and the rest of the space in the tank is occupied by air. The air pressure, inside the tank as well as outside it, is atmospheric. The acceleration due to gravity (\(g\)) acts vertically downward. The net horizontal force applied by the oil on the right hemispherical end (shown by the bold outline in the figure) is: