The number of radial nodes for an electron in an orbital is given by n - l - 1, where n is the principal quantum number and l is the azimuthal quantum number.
For an s orbital, l = 0, so the number of radial nodes is n - 1. For a p orbital, l = 1, so the number of radial nodes is n - 2.
Therefore, the number of radial nodes for each of the orbitals are:
5s: 5 - 1 - 0 = 4 radial nodes
6s: 6 - 1 - 0 = 5 radial nodes
7s: 7 - 1 - 0 = 6 radial nodes
6p: 6 - 2 - 1 = 3 radial nodes
4p: 4 - 2 - 1 = 1 radial node
Only the 6s orbital has five radial nodes. Therefore, only one of the given orbitals has five radial nodes.
Answer. 6s