Question:
How many moles of \(Ba_3(PO_4)_2\) will be formed by the reaction of \(5\) moles of \(BaCl_2\) and \(3\) moles of \(Na_3(PO_4)\).
How many moles of \(Ba_3(PO_4)_2\) will be formed by the reaction of \(5\) moles of \(BaCl_2\) and \(3\) moles of \(Na_3(PO_4)\).
Updated On: Feb 16, 2024
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Solution and Explanation
\(3\; BaCl_2 + 2\;Na_3 PO_4 → Ba_3(PO_4)_2 + 6\;NaCl\)
\(5\) \(mole\) \(3\) \(mole\)
\(\text{Moles of}\) \(Ba_3(PO_4)_2 = \frac{5}{3}\)
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Classification of Matter
There are two ways of classifying the matter:
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