Question:

How many grams of Albumin and Aspirin will be required to set a reaction between one millimole of Albumin and 0.5 millimole of Aspirin? Given the molecular weight of Albumin is 67,000 Da and that of Aspirin is 180 Da.

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When calculating the required mass of a substance, use the formula: \[ {Mass} = {moles} \times {molecular weight} \] Make sure to convert the units appropriately.
Updated On: Apr 17, 2025
  • 1 g, 1 mg
  • 67 g, 90 mg
  • 0.1 g, 70 mg
  • 67 µg, 90 mg
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The Correct Option is B

Solution and Explanation

Given:
Molecular weight of Albumin = 67,000 Da
Molecular weight of Aspirin = 180 Da
1 millimole of Albumin = \(1 \times 10^{-3}\) moles
0.5 millimole of Aspirin = \(0.5 \times 10^{-3}\) moles

Step 1: Calculate the mass of Albumin required

Using the formula:
Mass = moles × molecular weight
For Albumin:
Mass of Albumin = 1 × 10-3 moles × 67,000 g/mol = 67 g

Step 2: Calculate the mass of Aspirin required

For Aspirin:
Mass of Aspirin = 0.5 × 10-3 moles × 180 g/mol = 0.09 g = 90 mg

Thus, the correct amounts are:
Albumin: 67 g
Aspirin: 90 mg

So, the correct answer is \( \boxed{67 \, \text{g}, 90 \, \text{mg}} \).

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