Given:
Molecular weight of Albumin = 67,000 Da
Molecular weight of Aspirin = 180 Da
1 millimole of Albumin = \(1 \times 10^{-3}\) moles
0.5 millimole of Aspirin = \(0.5 \times 10^{-3}\) moles
Using the formula:
Mass = moles × molecular weight
For Albumin:
Mass of Albumin = 1 × 10-3 moles × 67,000 g/mol = 67 g
For Aspirin:
Mass of Aspirin = 0.5 × 10-3 moles × 180 g/mol = 0.09 g = 90 mg
Thus, the correct amounts are:
Albumin: 67 g
Aspirin: 90 mg
So, the correct answer is \( \boxed{67 \, \text{g}, 90 \, \text{mg}} \).