Understanding the Problem
We need to find the maximum distance in the line of sight between two antennas using the formula:
\( d = \sqrt{2Rh_t + 2Rh_r} \)
where:
Corrected Solution
1. Convert Units:
Since \(R\) is in kilometers, we need to convert \(h_t\) and \(h_r\) to kilometers.
\( h_t = 180 \, \text{m} = 0.18 \, \text{km} \)
\( h_r = 245 \, \text{m} = 0.245 \, \text{km} \)
2. Substitute Values into the Formula:
\( d = \sqrt{2(6400)(0.18) + 2(6400)(0.245)} \)
\( d = \sqrt{2(6400)(0.18 + 0.245)} \)
\( d = \sqrt{12800(0.425)} \)
\( d = \sqrt{5440} \)
3. Calculate the Distance:
\( d \approx 73.76 \, \text{km} \)
Error in Your Calculation
You directly added the heights in meters and multiplied them by the radius in kilometers without converting the heights to kilometers. This led to a significantly larger and incorrect result.
Final Answer
The maximum distance in the line of sight between the two antennas is approximately \( 73.76 \, \text{km} \).
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
A system that describes the information exchange between two points is called the communication system. The transmission and reception process of information is called communication. The major elements of communication are such as:
The following are the examples of communication systems:
Turning on Signal specification or technology, the communication system is categorized as follows: