Question:
$ HCl $ behaves as......in the reaction: $ HCl+HF\xrightarrow{{}}H_{2}^{+}Cl+{{F}^{-}} $
$ HCl $ behaves as......in the reaction: $ HCl+HF\xrightarrow{{}}H_{2}^{+}Cl+{{F}^{-}} $
Updated On: Jun 7, 2022
- weak base
- weak acid
- strong base
- strong acid
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The Correct Option is A
Solution and Explanation
In the reaction, $ HCl+HF\xrightarrow{{}}H_{2}^{+}Cl+{{F}^{-}} $ $ HCl $ is taking up a proton, hence it is acting as a base. Its conjugate acid $ (H_{2}^{+}Cl) $ has a strong tendency to loose proton, hence it is a strong acid, and therefore, its conjugate base (HC1) will be a weaker base.
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family