Given that dy/dx = yex such that x = 0, y = e. The value of y(y > 0) when x = 1 will be
e
1/e
ee
e2
The correct answer is option C) ee
Given that dy/dx = yex
such that x = 0, y = e.
The value of y(y > 0) when x = 1 will be
dy/y = exdx
⇒ ln y = ex + c
At x = 0, y = e.
So, c = 0. ln y = ex
Therefore, at x = 1, y = ee.
Let be a twice differentiable function such that for all . If and satisfies , where , then the area of the region R = {(x, y) | 0 y f(ax), 0 x 2\ is :
For the circuit shown above, the equivalent gate is: