Given that dy/dx = yex such that x = 0, y = e. The value of y(y > 0) when x = 1 will be
Given that dy/dx = yex such that x = 0, y = e. The value of y(y > 0) when x = 1 will be
e
1/e
ee
e2
The Correct Option is C
Solution and Explanation
The correct answer is option C) ee
Given that dy/dx = yex
such that x = 0, y = e.
The value of y(y > 0) when x = 1 will be
dy/y = exdx
⇒ ln y = ex + c
At x = 0, y = e.
So, c = 0. ln y = ex
Therefore, at x = 1, y = ee.
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