To find the distance from the lens where an object must be placed so that the image forms on the object itself, we use the formula for a lens with one side completely polished, acting as a combination of a lens and a mirror.
When light travels through a lens and reflects back from a polished surface, the effective focal length (\( f \)) can be calculated using the lens maker's formula combined with the mirror equation.
First, consider the lens maker's formula for a thin lens:
\( \frac{1}{f} = (\mu - 1) \left(\frac{1}{R_1} - \frac{1}{R_2}\right) \)
Given that one side is polished, \( R_2 = -R \). Since it's acting as a mirror, its focal length will be:
\( \frac{1}{f} = (\mu - 1) \left(\frac{1}{R} - \frac{1}{-R}\right) = (\mu - 1) \left(\frac{2}{R}\right) \)
Simplifying gives:
\( f = \frac{R}{2(\mu - 1)} \)
For the image to form at the position of the object, the object distance (\( u \)) must equal the image distance (\( v \)). Thus, when derived, the position where the object needs to be placed is:
\( u = \frac{R}{2(\mu - 1)} \)
Therefore, the correct answer is:
\( \frac{R}{2(\mu - 1)} \)