Question

Given below are two statements:

 Statement I

 under Clemmensen reduction conditions will give

 Statement II

 under Wolff-Kishner reduction condition will give

 In the light of the above statements, choose the correct answer from the options given below:

• A. Statement I is true but Statement II is false
• B. Statement I is false but Statement II is true
• C. Both Statement I and Statement II are true
• D. Both Statement I and Statement II are false

Hint:

Clemmensen Reduction: Reduces ketones or aldehydes to alkanes under acidic conditions.
Wolff-Kishner Reduction: Reduces ketones or aldehydes to alkanes under basic conditions, but reactive substituents like halogens may undergo side reactions.

Answer 1

The Correct Option is A

Statement I:
Clemmensen reduction involves the use of Zn(Hg) and HCl, which reduces ketones or aldehydes to their corresponding alkanes under acidic conditions.
In the given compound, \(\text{H}_2\text{N} - \text{CH}_2\text{CH}_2\text{COCH}_3\), the ketone group (\(\text{COCH}_3\)) is reduced, and the intermediate carboxylic acid product (\(\text{HOOC-CH}_2\text{CH}_2\)) is correct under these conditions.
Hence, Statement I is true.
Statement II:
Wolff-Kishner reduction involves hydrazine (\(\text{NH}_2\text{NH}_2\)) and a strong base such as KOH, which reduces carbonyl groups (ketones or aldehydes) to their corresponding alkanes.
However, in the compound \(\text{Cl-CH}_2\text{CH}_2\text{COCH}_3\), the chlorine atom may react with the basic medium, leading to a side reaction (dehydrohalogenation) instead of simple reduction. The final product will not necessarily be \(\text{ClCH}_2\text{CH}_2\text{CH}_3\), as suggested.
Hence, Statement II is false.