Solution:
Statement I: SbCl5 is more covalent than SbCl3
This statement is correct. According to Fajan's rules, higher oxidation states of the central atom lead to greater polarization of the anion, resulting in increased covalent character. Sb in SbCl5 has a +5 oxidation state, while in SbCl3, it has a +3 oxidation state. Therefore, SbCl5 is more covalent than SbCl3.
Statement II: The higher oxides of halogens also tend to be more stable than the lower ones.
This statement is also correct. Higher oxides of halogens are generally more stable due to the greater covalent character and stronger bonds formed. For example, Cl2O7 is more stable than Cl2O.
Therefore, both Statement I and Statement II are correct.
Correct Answer: (1) Both statement I and Statement II are correct
Among the following cations, the number of cations which will give characteristic precipitate in their identification tests with
\(K_4\)[Fe(CN)\(_6\)] is : \[ {Cu}^{2+}, \, {Fe}^{3+}, \, {Ba}^{2+}, \, {Ca}^{2+}, \, {NH}_4^+, \, {Mg}^{2+}, \, {Zn}^{2+} \]
A solution of aluminium chloride is electrolyzed for 30 minutes using a current of 2A. The amount of the aluminium deposited at the cathode is _________
If \( z \) is a complex number and \( k \in \mathbb{R} \), such that \( |z| = 1 \), \[ \frac{2 + k^2 z}{k + \overline{z}} = kz, \] then the maximum distance from \( k + i k^2 \) to the circle \( |z - (1 + 2i)| = 1 \) is: