Question

Given below are two statements:
Statement I: Methane and steam passed over a heated Ni catalyst produces hydrogen gas.
Statement II: Sodium nitrate reacts with NH\(_4\)Cl to give H\(_2\)O and NaCl.

• A. Both the statement I and II are incorrect
• B. Statement I is incorrect but statement II is correct
• C. Statement I is correct but statement II is incorrect
• D. Both the statements I and II are correct

Hint:

The reaction of methane and steam over a nickel catalyst is a classic example of a reforming reaction, where hydrogen gas is generated.

Answer 1

The Correct Option is D

- Statement I is correct. When methane reacts with steam over a nickel catalyst, hydrogen gas is produced in the reaction: \[ CH_4(g) + H_2O(g) \xrightarrow{Ni} CO(g) + 3H_2(g) \] - Statement II is correct. Sodium nitrate reacts with ammonium chloride to give sodium chloride and water in the reaction: \[ NaNO_3(aq) + NH_4Cl(aq) \rightarrow NaCl(aq) + NaNO_3(aq) + H_2O \] Thus, the correct answer is (4), Both the statements I and II are correct.