Question

Given below are two statements:
Statement I : Ethene at 333 to 343 K and 6-7 atm pressure in the presence of AIEt₃ and TiCl₄ undergoes addition polymerization to give LDP.
Statement II: Caprolactam at 533-543 K in H₂O through step growth polymerizes to give Nylon 6.
In the light of the above statements, choose the correct answer from the options given below:

• A. Both Statement t and Statement II are false
• B. Statement I is true but Statement II is false
• C. Both Statement I and Statement II are true
• D. Statement I is false but Statement II is true

Answer 1

The Correct Option is D

Statement I:

Ethene at 333–343 K and 6–7 atm pressure in the presence of \( \text{AlEt}_3 \) and \( \text{TiCl}_4 \) undergoes addition polymerization to give high-density polyethylene (HDPE), not low-density polyethylene (LDPE).

• HDPE is produced using Ziegler-Natta catalysts (\( \text{AlEt}_3 \) and \( \text{TiCl}_4 \)) under moderate temperatures and pressures.
• LDPE, on the other hand, is produced via free radical polymerization at much higher temperatures (423–573 K) and very high pressures (1000–2000 atm).
• Thus, Statement I is false.

Statement II:

Caprolactam undergoes ring-opening polymerization in the presence of water at high temperatures (533–543 K) to form Nylon 6. This is an example of step-growth polymerization.

The reaction can be represented as

Thus, Statement II is true.

Final Answer:

Statement I is false, but Statement II is true.