Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): Emission of electrons in photoelectric effect can be suppressed by applying a sufficiently negative electron potential to the photoemissive substance.
Reason (R): A negative electric potential, which stops the emission of electrons from the surface of a photoemissive substance, varies linearly with frequency of incident radiation.
In light of the above statements, choose the most appropriate answer from the options given below:
- Assertion (A) is correct because the photoelectric effect can indeed be suppressed by applying a sufficiently negative potential to the material, as the energy required to remove electrons becomes greater than the energy provided by the incident radiation.
- Reason (R) is also correct, as a negative electric potential does indeed stop the emission of electrons, but it does not depend on the frequency of the incident radiation, but rather on the energy required to overcome the binding energy of the electrons. Thus, (R) is correct but does not explain (A) fully. The correct answer is option (1).
In photoelectric effect, the stopping potential \( V_0 \) vs frequency \( \nu \) curve is plotted. \( h \) is the Planck's constant and \( \phi_0 \) is the work function of metal.
(A) \( V_0 \) vs \( \nu \) is linear.
(B) The slope of \( V_0 \) vs \( \nu \) curve is \( \frac{\phi_0}{h} \).
(C) \( h \) constant is related to the slope of \( V_0 \) vs \( \nu \) line.
(D) The value of electric charge of electron is not required to determine \( h \) using the \( V_0 \) vs \( \nu \) curve.
(E) The work function can be estimated without knowing the value of \( h \). \text{Choose the correct answer from the options given below:}
N equally spaced charges each of value \( q \) are placed on a circle of radius \( R \). The circle rotates about its axis with an angular velocity \( \omega \) as shown in the figure. A bigger Amperian loop \( B \) encloses the whole circle, whereas a smaller Amperian loop \( A \) encloses a small segment. The difference between enclosed currents, \( I_B - I_A \) for the given Amperian loops is: