Glycine (\( \text{NH}_2\text{CH}_2\text{COOH} \)) reacts with chlorine (\( \text{Cl}_2 \)) in the presence of red phosphorus to undergo alpha-halogenation. The reaction produces 2-chloroacetic acid (\( \text{NH}_2\text{CHClCOOH} \)) as the product:
\[ \text{NH}_2\text{CH}_2\text{COOH} + \text{Cl}_2 \xrightarrow{\text{Red P}} \text{NH}_2\text{CHClCOOH} \]
In the product, 2-chloroacetic acid (\( \alpha \)-chloroacetic acid), the carbon marked with an asterisk is a chiral carbon:
This assertion is true.
The reason states that a molecule with two chiral carbons is always optically active. This is false, as a molecule with two chiral centers can be optically inactive if it has an internal plane of symmetry. Such molecules are called meso compounds.
Assertion (A) is true, but Reason (R) is false.
If all the words with or without meaning made using all the letters of the word "KANPUR" are arranged as in a dictionary, then the word at 440th position in this arrangement is:
If the system of equations \[ x + 2y - 3z = 2, \quad 2x + \lambda y + 5z = 5, \quad 14x + 3y + \mu z = 33 \] has infinitely many solutions, then \( \lambda + \mu \) is equal to:}
The equilibrium constant for decomposition of $ H_2O $ (g) $ H_2O(g) \rightleftharpoons H_2(g) + \frac{1}{2} O_2(g) \quad (\Delta G^\circ = 92.34 \, \text{kJ mol}^{-1}) $ is $ 8.0 \times 10^{-3} $ at 2300 K and total pressure at equilibrium is 1 bar. Under this condition, the degree of dissociation ($ \alpha $) of water is _____ $\times 10^{-2}$ (nearest integer value). [Assume $ \alpha $ is negligible with respect to 1]