In an Ellingham diagram, a negative slope indicates that the reaction becomes more favorable at higher temperatures, while a positive slope indicates that the reaction becomes less favorable.
Assertion A is correct: In an Ellingham diagram, the oxidation of carbon to carbon monoxide does indeed show a negative slope, indicating that the reaction becomes more favorable as temperature increases.
Reason R is incorrect: While CO is a reducing agent, it does not tend to decompose at higher temperatures; rather, the decomposition of CO to C and \( \text{O}_2 \) is unfavorable at high temperatures, as shown by its position on the Ellingham diagram.
Conclusion: The correct answer is 4.

Consider that specific heat (0 to \(50~^\circ\mathrm{C}\)) of water, water vapour and air remains constant: \(4.48\), \(1.88\) and \(1.0~\mathrm{kJ/(kg\^\circ C)}\), respectively. Assuming the heat energy required to convert \(1~\mathrm{kg}\) of water to water vapour at \(0~^\circ\mathrm{C}\) is \(2000~\mathrm{kJ}\), the enthalpy (in kJ/kg dry air) of atmospheric air containing \(0.05~\mathrm{kg}\) water vapour per kg dry air at \(50~^\circ\mathrm{C}\) is ________. (rounded off to 1 decimal place)
Minerals are the naturally occurring, homogeneous inorganic solid substances. They are having a definite chemical composition and crystalline structure, hardness and color. For example, copper pyrite, calamine, etc.

Impurities in an ore are called gauge. The removal of a gauge from the ore is called concentration ore.
Several steps are involved in the extraction of pure metal from ores. Major steps are as follows –