To solve this question, we need to analyze both the assertion and the reason provided, and determine if each statement is correct and if the reason is a valid explanation for the assertion.
The work done by an electric field when moving a charge on an equipotential surface is zero
because there is no change in electric potential energy. Electric lines of force are always
perpendicular to equipotential surfaces, meaning that any movement along the surface does
not alter the electric potential, confirming that no work is done.
The Correct answer is: Both (A) and (R) are correct and (R) is the correct explanation of (A)
Match List-I with List-II.
Choose the correct answer from the options given below :}
There are three co-centric conducting spherical shells $A$, $B$ and $C$ of radii $a$, $b$ and $c$ respectively $(c>b>a)$ and they are charged with charges $q_1$, $q_2$ and $q_3$ respectively. The potentials of the spheres $A$, $B$ and $C$ respectively are:
Two resistors $2\,\Omega$ and $3\,\Omega$ are connected in the gaps of a bridge as shown in the figure. The null point is obtained with the contact of jockey at some point on wire $XY$. When an unknown resistor is connected in parallel with $3\,\Omega$ resistor, the null point is shifted by $22.5\,\text{cm}$ towards $Y$. The resistance of unknown resistor is ___ $\Omega$. 
Which one of the following graphs accurately represents the plot of partial pressure of CS₂ vs its mole fraction in a mixture of acetone and CS₂ at constant temperature?
