Solution:
Using Gauss's Law:
\[
\Phi = \frac{Q_{\text{in}}}{\epsilon_0}
\]
Since the electric dipole has no net charge (it consists of equal and opposite charges), the net charge \( Q_{\text{in}} = 0 \). Hence, the net flux \( \Phi = 0 \).
Thus, Assertion A is true.
Reason R states that an electric dipole consists of two equal and opposite charges, which is true.
Thus, both Assertion A and Reason R are true, and Reason R correctly explains Assertion A.
Therefore, the correct answer is \( \boxed{1} \).
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): Net dipole moment of a polar linear isotropic dielectric substance is not zero even in the absence of an external electric field. Reason
(R): In absence of an external electric field, the different permanent dipoles of a polar dielectric substance are oriented in random directions.
In the light of the above statements, choose the most appropriate answer from the options given below:
Two large plane parallel conducting plates are kept 10 cm apart as shown in figure. The potential difference between them is $ V $. The potential difference between the points A and B (shown in the figure) is: 
A metallic ring is uniformly charged as shown in the figure. AC and BD are two mutually perpendicular diameters. Electric field due to arc AB to O is ‘E’ magnitude. What would be the magnitude of electric field at ‘O’ due to arc ABC? 

\[ f(x) = \left\{ \begin{array}{ll} 1 - 2x & \text{if } x < -1 \\ \frac{1}{3}(7 + 2|x|) & \text{if } -1 \leq x \leq 2 \\ \frac{11}{18} (x-4)(x-5) & \text{if } x > 2 \end{array} \right. \]