Solution:
Using Gauss's Law:
\[
\Phi = \frac{Q_{\text{in}}}{\epsilon_0}
\]
Since the electric dipole has no net charge (it consists of equal and opposite charges), the net charge \( Q_{\text{in}} = 0 \). Hence, the net flux \( \Phi = 0 \).
Thus, Assertion A is true.
Reason R states that an electric dipole consists of two equal and opposite charges, which is true.
Thus, both Assertion A and Reason R are true, and Reason R correctly explains Assertion A.
Therefore, the correct answer is \( \boxed{1} \).
If $ \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p $, then $ 96 \log_e p $ is equal to _______