Solution:
Using Gauss's Law:
\[
\Phi = \frac{Q_{\text{in}}}{\epsilon_0}
\]
Since the electric dipole has no net charge (it consists of equal and opposite charges), the net charge \( Q_{\text{in}} = 0 \). Hence, the net flux \( \Phi = 0 \).
Thus, Assertion A is true.
Reason R states that an electric dipole consists of two equal and opposite charges, which is true.
Thus, both Assertion A and Reason R are true, and Reason R correctly explains Assertion A.
Therefore, the correct answer is \( \boxed{1} \).
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: