The correct answer is (D):
Any equilateral triangle formed by joining the midpoints of the sides of another equilateral triangle will have its side equal to half the side of the second equilateral triangle.
Side of T1 = 24 cm Side of T2 = 12 cm Side of T3 = 6 cm and so on.
Sum of the areas of all the triangles = √3/4(242+122+62+....)
= √3/4(576/1-1/4)=192√3
ABCD is a trapezoid where BC is parallel to AD and perpendicular to AB . Kindly note that BC<AD . P is a point on AD such that CPD is an equilateral triangle. Q is a point on BC such that AQ is parallel to PC . If the area of the triangle CPD is 4√3. Find the area of the triangle ABQ.