Given a non empty set X, consider P(X) which is the set of all subsets of X.
Define the relation R in P(X) as follows:
For subsets A,B in P(X),ARB if and only if A⊂B.
Is R an equivalence relation on P(X)? Justify you answer:
Since every set is a subset of itself, ARA for all A ∈ P(X).
∴R is reflexive.
Let ARB ⇒ A ⊂ B.
This cannot be implied to B ⊂ A.
For instance, if A = {1, 2} and B = {1, 2, 3},
then it cannot be implied that B is related to A.
∴ R is not symmetric.
Further, if ARB and BRC,
then A ⊂ B and B ⊂ C.
\(\Rightarrow\) A ⊂ C \(\Rightarrow\) ARC
∴ R is transitive.
Hence, R is not an equivalence relation since it is not symmetric.
LIST I | LIST II | ||
A. | Range of y=cosec-1x | I. | R-(-1, 1) |
B. | Domain of sec-1x | II. | (0, π) |
C. | Domain of sin-1x | III. | [-1, 1] |
D. | Range of y=cot-1x | IV. | \([\frac{-π}{2},\frac{π}{2}]\)-{0} |
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