The relation \( R \) contains pairs of students' roll numbers such that the second roll number is three times the first.
Thus, if \( x \) is the roll number of a student, then \( y = 3x \) is the roll number of another student. For example, if the roll numbers of the students are \( 1, 2, 3, 4, 5, 6, \dots, 10 \), the elements of \( R \) will be: \[ R = \{ (1, 3), (2, 6), (3, 9) \} \]
Now, let's check if the relation is reflexive, symmetric, and transitive:
1. Reflexive: A relation is reflexive if every element is related to itself. For reflexivity, we would need \( (x, x) \in R \) for all \( x \).
Since \( y = 3x \), it is impossible for \( y = x \), so \( R \) is not reflexive.
2. Symmetric: A relation is symmetric if whenever \( (x, y) \in R \), then \( (y, x) \in R \). Since \( y = 3x \), there is no corresponding pair \( (y, x) \) where \( x = 3y \), so \( R \) is not symmetric.
3. Transitive: A relation is transitive if whenever \( (x, y) \in R \) and \( (y, z) \in R \), then \( (x, z) \in R \). Since \( y = 3x \) and \( z = 3y = 9x \), we see that \( (x, z) = (x, 9x) \) is also in \( R \).
Hence, the relation is transitive.
A carpenter needs to make a wooden cuboidal box, closed from all sides, which has a square base and fixed volume. Since he is short of the paint required to paint the box on completion, he wants the surface area to be minimum.
On the basis of the above information, answer the following questions :
Find a relation between \( x \) and \( y \) such that the surface area \( S \) is minimum.
Let \( R \) be a relation defined by \( R = \{(x, y) : x, y \text{ are Roll Numbers of students such that } y = x^3 \} \). List the elements of \( R \). Is \( R \) a function? Justify your answer.
A school is organizing a debate competition with participants as speakers and judges. $ S = \{S_1, S_2, S_3, S_4\} $ where $ S = \{S_1, S_2, S_3, S_4\} $ represents the set of speakers. The judges are represented by the set: $ J = \{J_1, J_2, J_3\} $ where $ J = \{J_1, J_2, J_3\} $ represents the set of judges. Each speaker can be assigned only one judge. Let $ R $ be a relation from set $ S $ to $ J $ defined as: $ R = \{(x, y) : \text{speaker } x \text{ is judged by judge } y, x \in S, y \in J\} $.
Let \(\mathbf{a}, \mathbf{b}\) and \(\mathbf{c}\) be three vectors such that \(\mathbf{a} \times \mathbf{b} = \mathbf{a} \times \mathbf{c}\) and \(\mathbf{a} \times \mathbf{b} \neq 0. Show \;that \;\mathbf{b} = \mathbf{c}\).
If $y = 5 \cos x - 3 \sin x$, prove that $\frac{d^2y}{dx^2} + y = 0$.