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given a i 2 b i 2 c i 2 1 and a i a j b i b j c i
Question:
Given $a_i^2 + b_i^2 + c_i^2 = 1$ and $a_i a_j + b_i b_j + c_i c_j = 0$ for $i \neq j$, and
\[ A = \begin{bmatrix} a_1 & a_2 & a_3 \\ b_1 & b_2 & b_3 \\ c_1 & c_2 & c_3 \end{bmatrix} \]
Then
$\det(AA^T) = $ ?
Show Hint
For orthogonal matrices, $AA^T = I$, so $\det(AA^T) = 1$
AP EAPCET - 2022
AP EAPCET
Updated On:
May 18, 2025
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The Correct Option is
B
Solution and Explanation
Given vectors are orthonormal (dot products zero for $i \ne j$ and each has magnitude 1), hence matrix $A$ is orthogonal.
So $AA^T = I \Rightarrow \det(AA^T) = \det(I) = 1$
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