The correct answer is (B):
Thin Crust pizzas delivered to party 3 = z + 162 – z = 162.
The correct answer is (C):
Total Normal Cheese pizzas delivered to the three parties = 0.52 (800) = 416
From the table,
416 = (x + y +z) + (w +36 –y + 364 – z)
416 = 400 + w + x
⇒ w + x = 16
So, party 1 ordered 16 Normal Cheese pizzas.
The correct answer is (B):
Given, of the 36 Normal Cheese pizzas delivered to party 2, 50% or 18 were of Thin Crust variety ∴ y = 18. Difference between 66 – y and 18 + y
= 48 –2y
= 48 – 36
= 12
The correct answer is (A):
We already know, w + x = 16 Further, we’re told that of the x + w Normal Cheese pizzas delivered to party 1, 25% are of Deep Dish variety.
∴ w/x+w = 1/4 ⇒ x = 3w
So, x = 12 and w = 4
Cost of a T-EC pizza = ` 500
Cost of a D-EC pizza = ` 550
Cost of a T-NC pizza = ` 330
Cost of a D-NC pizza = ` 330
Total pizza bill for part 1
= 12 (330) + 60(500) + 4(330) + 44(550)
= ₹ 59,480