Step 1: Understanding the Question
We are required to find the minimum cost to complete a given work within 10 days using three workers who differ in both working efficiency and daily wages. The goal is to identify the most cost-effective worker(s) and ensure the work is completed within the given time limit.
Step 2: Key Approach
Step 3: Detailed Solution
Part A: Rates of Work and Pay
Part B: Efficiency (Cost per Unit of Work)
Let total work be the LCM of 24, 21, and 15: \[ \text{Total Work} = 840 \text{ units} \]
Arun and Varun are the most economical workers, each costing \( \frac{18}{7} \) rs/unit, while Tarun is comparatively expensive.
Part C: Minimum Cost Calculation
To minimize cost, we use only Arun and Varun.
Combined work rate: \[ 35 + 56 = 91 \text{ units/day} \] Time required: \[ \frac{840}{91} \approx 9.23 \text{ days} \] Since this is less than 10 days, the strategy is valid.
Minimum cost: \[ 840 \times \frac{18}{7} = 120 \times 18 = 2160 \]
Step 4: Final Answer
The minimum amount that has to be paid is ₹2160.
For any natural number $k$, let $a_k = 3^k$. The smallest natural number $m$ for which \[ (a_1)^1 \times (a_2)^2 \times \dots \times (a_{20})^{20} \;<\; a_{21} \times a_{22} \times \dots \times a_{20+m} \] is: