Question

From the given transfer characteristic of a transistor in CE configuration, the value of power gain of this configuration is 10^x, for R_B = 10 kΩ, and R_c = 1 kΩ. The value of x is_____.

Hint:

Power gain in a CE transistor configuration depends on the current gain (\( \beta \)) and the resistance values of \( R_C \) and \( R_B \). Always ensure proper unit consistency when calculating.

Answer 1

Correct Answer: 3

Solution:
To find the value of \( x \), we calculate the power gain using the relation: \[ \text{Power Gain} = \beta \times \frac{R_C}{R_B}. \] Step 1: Calculate Current Gain (\( \beta \))
From the given graph,
\[ \beta = \frac{I_C}{I_B}. \] For \( I_C = 50 \, \text{mA} \) and \( I_B = 500 \, \mu\text{A} \): \[ \beta = \frac{50 \times 10^{-3}}{500 \times 10^{-6}} = 100. \] Step 2: Calculate Power Gain
Substitute \( \beta = 100 \), \( R_C = 1 \, \text{k}\Omega \), and \( R_B = 10 \, \text{k}\Omega \) into the power gain formula: \[ \text{Power Gain} = \beta \times \frac{R_C}{R_B} = 100 \times \frac{1}{10} = 10. \] Step 3: Find \( x \)
Since the power gain is \( 10^x \): \[ 10^x = 10 \quad \Rightarrow \quad x = 1. \]