Question:
From the given information, calculate enthalpy of formation of 2 moles of $C_6H_6$(l) at 25°C. Given: $CH(C_6H_6$(l)) = –3264.6 kJ/mol $CH(C(s))$ = –393.5 kJ/mol $fH(H_2O(l))$ = –285.83 kJ/mol
From the given information, calculate enthalpy of formation of 2 moles of $C_6H_6$(l) at 25°C. Given: $CH(C_6H_6$(l)) = –3264.6 kJ/mol $CH(C(s))$ = –393.5 kJ/mol $fH(H_2O(l))$ = –285.83 kJ/mol
Updated On: Sep 17, 2024
- –124.5 kJ/mol
- –46.11 kJ/mol
- 46.11 kJ/mol
- 124.5 kJ/mol
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
The Correct answer is option is (C) : 46.11 kJ/mol
Was this answer helpful?
0
0
Top Questions on Enthalpy change
- The bond dissociation energies of gaseous H2, Cl2, and HCl are 104, 58, and 103 kcal, respectively. The enthalpy of formation of HCl gas would be:
- BCECE - 2025
- Chemistry
- Enthalpy change
- What is the enthalpy of neutralization for CH3COOH + NaOH?
- BCECE - 2025
- Chemistry
- Enthalpy change
- The electron gain enthalpy (Cl2,H) of chlorine is -3.7 eV mol-1. How much energy (in kcal mol-1) is released when 71 g of chlorine atoms are completely converted into Cl- ions in gaseous state? (1 eV = 23 kcal)
- AP EAPCET - 2025
- Chemistry
- Enthalpy change
- Calculate the enthalpy change ($\Delta H$) for the combustion of 1 mole of methane ($\mathrm{CH}_4$) given the reaction: $$ \mathrm{CH}_4(g) + 2 \mathrm{O}_2(g) \rightarrow \mathrm{CO}_2(g) + 2 \mathrm{H}_2 \mathrm{O}(l) $$ Given bond energies: C–H = 413 kJ/mol, O=O = 498 kJ/mol, C=O = 803 kJ/mol, O–H = 467 kJ/mol.
- AP EAPCET - 2025
- Chemistry
- Enthalpy change
The enthalpy of combustion of methane is 890 kJ/mol. How much heat is released when 8 g of methane is burned completely? (Molar mass of CH\(_4\) = 16 g/mol)
- AP EAPCET - 2025
- Chemistry
- Enthalpy change
View More Questions
Questions Asked in JEE Main exam
- Let \( a_1, a_2, a_3, \dots \) be a G.P. of increasing positive terms. If \( a_1 a_5 = 28 \) and \( a_2 + a_4 = 29 \), then the value of \( a_6 \) is equal to:
- JEE Main - 2025
- Sequences and Series
A force \( \vec{f} = x^2 \hat{i} + y \hat{j} + y^2 \hat{k} \) acts on a particle in a plane \( x + y = 10 \). The work done by this force during a displacement from \( (0,0) \) to \( (4m, 2m) \) is Joules (round off to the nearest integer).
- JEE Main - 2025
- Work and Energy
- Consider a long thin conducting wire carrying a uniform current \( I \). A particle having mass \( M \) and charge \( q \) is released at a distance \( a \) from the wire with a speed \( v_0 \) along the direction of current in the wire. The particle gets attracted to the wire due to magnetic force. The particle turns round when it is at distance \( x \) from the wire. The value of \( x \) is:
- JEE Main - 2025
- Magnetic Field
- Two equal sides of an isosceles triangle are along \( -x + 2y = 4 \) and \( x + y = 4 \). If \( m \) is the slope of its third side, then the sum of all possible distinct values of \( m \) is:
- JEE Main - 2025
- 3D Geometry
- Let the position vectors of the vertices A, B, and C of a tetrahedron ABCD be \( \hat{i} + 2\hat{j} + \hat{k} \), \( \hat{i} + 3\hat{j} - 2\hat{k} \), and \( 2\hat{i} + \hat{j} - \hat{k} \) respectively. The altitude from the vertex D to the opposite face ABC meets the median line segment through A of the triangle ABC at the point E. If the length of AD is \( \frac{\sqrt{10}}{3} \) and the volume of the tetrahedron is \( \frac{\sqrt{805}}{6\sqrt{2}} \), then the position vector of E is:
- JEE Main - 2025
- Geometry and Vectors
View More Questions