If dydx+2ysec2x=2sec2x+3tanx⋅sec2x \frac{dy}{dx} + 2y \sec^2 x = 2 \sec^2 x + 3 \tan x \cdot \sec^2 x dxdy+2ysec2x=2sec2x+3tanx⋅sec2x and
and f(0)=54 f(0) = \frac{5}{4} f(0)=45, then the value of 12(y(π4)−1e2) 12 \left( y \left( \frac{\pi}{4} \right) - \frac{1}{e^2} \right) 12(y(4π)−e21) equals to: