To solve the problem, we need to find the value of $x$ using the properties of triangles and trigonometry.
1. Observing the Triangle Configuration:
In the given figure, triangles $\triangle ABC$ and $\triangle DEC$ share angle $\angle C$, and angles $\angle A = \angle E$ (both marked as equal), which means the triangles are similar by AA similarity.
2. Using Property of Similar Triangles:
From similar triangles $\triangle ABC \sim \triangle DEC$, the corresponding sides are in proportion:
$\frac{AB}{DE} = \frac{AC}{DC}$
3. Substituting Given Values:
$AB = 24$
$DE = 12$
$BC = 22$
Let $x = DC$
Using similar triangles, we write:
$\frac{24}{12} = \frac{22}{x}$
4. Solving the Proportion:
$\frac{24}{12} = 2$, so:
$2 = \frac{22}{x}$
$x = \frac{22}{2} = 11$
Final Answer:
The value of $x$ is $ \mathbf{11} $.