For the reaction given below:
\(CoCl_3.xNH_3 + AgNO_3 (aq) →\)
If two equivalents of AgCl precipitate out, then the value of x will be____.
The correct answer is 5
\(COCl_3 xNH3 + AgNO_3(ag) → AgCl ↓\)
2 mol
Two equivalents of AgCl precipitates out, which symbolises that there are two free Clions. The coordination number of Co is six. So, the ligands inside the coordination sphere should be six. Hence, the complex should be \([Co(NH_3)_5Cl]Cl_2.\)
\([CO(NH_3)_5Cl] Cl_2 + AgNO_3 → AgCl↓\)
2 mol
Hence, the value of x is 5.
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