Question:

For the hyperbola \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \), the locus of the point of intersection of the tangents at the endpoints of normal chords is:

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For hyperbolas, use standard identities and known results involving normals and tangents to quickly identify loci of special points.
Updated On: May 17, 2025
  • \( \frac{a^6}{x^2} + \frac{b^6}{y^2} = (a^2 + b^2)^2 \)
  • \( \frac{a^6}{x^2} + \frac{b^6}{y^2} = (a^2 + b^2)^2 \)
  • \( \frac{a^6}{x^2} - \frac{b^6}{y^2} = (a^2 - b^2)^2 \)
  • \( \frac{a^6}{x^2} + \frac{b^6}{y^2} = (a^2 - b^2)^2 \)
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The Correct Option is B

Solution and Explanation

This is a standard result in conics. For the hyperbola \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \), the normal chords are those perpendicular to the curve.
The tangents at endpoints of these chords intersect at points whose locus is given by: \[ \frac{a^6}{x^2} + \frac{b^6}{y^2} = (a^2 + b^2)^2 \] This is derived from the parametric coordinates of points on the hyperbola and analyzing the envelope of normal chords.
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