Question

For the given reactions
Sn²⁺ + 2e^– → Sn
Sn⁴⁺ + 4e^– → Sn
the electrode potentials are;
\(E^{∘}_{Sn^{2+}/Sn}=−0.140V \) and \(E^{∘}_{Sn^{4+}Sn} =−0.010 V.\)
The magnitude of standard electrode potential for \(Sn^{4+}/Sn^{2+}\) i.e.
\(E^{∘}_{Sn^{4+}/Sn^{2+}}\)
is _________ × 10^–2 V. (Nearest integer)

Answer 1

Correct Answer: 16

The correct answer is 16
\(Sn→Sn^{2+}+2e− E^{∘}_{1}=0.140 V\)
\(Sn^{4+} + 4e^{−}→Sn \) \(E^{∘}_{2}=0.010 V\)
\(Sn^{4+}+2e^{−}→Sn^{2+} \) \(E^{∘}_{cell}\)
\(E^{∘}_{cell}=\frac{n_2E_{2}^{∘}+n_1E^{∘}_{1}}{n}=\frac{4(0.010)+2(0.140)}{2}\)
\(E^{∘}_{cell}=0.16 V=16×10^{−2} V\)