For the differential equation \( \frac{d^3 y}{dx^3} = 0 \), \( y = ax^2 + bx + c \) is:
Show Hint
For higher order differential equations:
- Each integration introduces a constant.
- Order = number of arbitrary constants.
- Check form of solution against the integrated form.
We are given:
\[
\frac{d^3 y}{dx^3} = 0
\]
Integrating thrice:
\[
\frac{d^2 y}{dx^2} = A, \quad \frac{dy}{dx} = Ax + B, \quad y = \frac{A}{2}x^2 + Bx + C
\]
Thus the general solution is a quadratic in \( x \), which matches the form:
\[
y = ax^2 + bx + c
\]