In amplitude modulation (AM), the modulation index (\(\mu\)) describes the extent of amplitude variation relative to the unmodulated carrier.
It is defined in terms of the maximum amplitude (\(A_{max}\)) and minimum amplitude (\(A_{min}\)) of the modulated wave as follows: \[ \mu = \frac{A_{max} - A_{min}}{A_{max} + A_{min}} \] Given values from the problem statement are:
- Maximum amplitude, \(A_{max} = 16 \, V\)
- Minimum amplitude, \(A_{min} = 4 \, V\)
Substituting these values into the modulation index formula: \[ \mu = \frac{16 \, V - 4 \, V}{16 \, V + 4 \, V} = \frac{12 \, V}{20 \, V} = \frac{12}{20} = \frac{3}{5} = 0.6 \] The modulation index is 0.6. Comparing this with the given options, option (3) matches our calculated value.
Correct Answer: (3) 0.6
Find the least horizontal force \( P \) to start motion of any part of the system of three blocks resting upon one another as shown in the figure. The weights of blocks are \( A = 300 \, {N}, B = 100 \, {N}, C = 200 \, {N} \). The coefficient of friction between \( A \) and \( C \) is 0.3, between \( B \) and \( C \) is 0.2 and between \( C \) and the ground is 0.1.