Heat transmission causes an entropy shift, which is measurable. The ratio of heat to the temperature at which transfer occurred gives the change in entropy. This process is isothermal if the heat transfer \(Q\) occurs at a single temperature, and the change in entropy is represented by the equation:
\(\Delta S = \frac{Q}{T}\)
According to the second law of thermodynamics, the entropy of a closed system increases for irreversible processes while remaining constant for reversible ones. In a closed system, entropy can never decrease:
\(\Delta S \geq 0\)
Measurable initial and final states are \(i\) and \(f\) for an ideal gas, respectively.
The entropy change is given by:
\(\Delta S = \int_{i}^{f} \frac{dQ}{T}\)
If the temperature is constant, we can simplify this as:
\(\Delta S = \frac{1}{T} \int_{i}^{f} dQ_{rev}\)
The reversible heat transfer is given by:
\(dQ_{rev} = -dW_{rev} = nRT \left( \frac{dV}{V} \right)\)
Substituting this into the equation for entropy change:
\(\Delta S = \frac{1}{T} \int_{i}^{f} nRT \frac{dV}{V}\)
This simplifies to:
\(\Delta S = \frac{nRT}{T} \int_{i}^{f} \left( \frac{dV}{V} \right)\)
Integrating, we get the entropy change as:
\(\Delta S = nR \ln \left( \frac{V_f}{V_i} \right)\) --- (1)
From Charle’s law, we know:
\(P_i V_i = P_f V_f\)
Rearranging this equation gives:
\(\frac{V_f}{V_i} = \frac{P_f}{P_i}\) --- (2)
Substituting equation (2) into equation (1), we get:
\(\Delta S = nR \ln \left( \frac{P_f}{P_i} \right)\)
Therefore, for a sample of a perfect gas when its pressure is changed isothermally from \( P_i \) to \( P_f \), the entropy change is:
\(\Delta S = nR \ln \left( \frac{P_f}{P_i} \right)\)
The correct answer is Option B.
Consider the following statements:
(A) Availability is generally conserved.
(B) Availability can neither be negative nor positive.
(C) Availability is the maximum theoretical work obtainable.
(D) Availability can be destroyed in irreversibility's.
List-I (Details of the processes of the cycle) | List-II (Name of the cycle) |
---|---|
(A) Two adiabatic, one isobaric and two isochoric | (I) Diesel |
(B) Two adiabatic and two isochoric | (II) Carnot |
(C) Two adiabatic, one isobaric and one isochoric | (III) Dual |
(D) Two adiabatics and two isothermals | (IV) Otto |
Given below are two statements: One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): A typical unfertilized, angiosperm embryo sac at maturity is 8-nucleate and 7-celled.
Reason (R): The egg apparatus has 2 polar nuclei.
In the light of the above statements, choose the correct answer from the options given below:
Thermodynamics in physics is a branch that deals with heat, work and temperature, and their relation to energy, radiation and physical properties of matter.
A thermodynamic system is a specific portion of matter with a definite boundary on which our attention is focused. The system boundary may be real or imaginary, fixed or deformable.
There are three types of systems:
A system undergoes a thermodynamic process when there is some energetic change within the system that is associated with changes in pressure, volume and internal energy.
There are four types of thermodynamic process that have their unique properties, and they are:
The Zeroth law of thermodynamics states that if two bodies are individually in equilibrium with a separate third body, then the first two bodies are also in thermal equilibrium with each other.
The First law of thermodynamics is a version of the law of conservation of energy, adapted for thermodynamic processes, distinguishing three kinds of transfer of energy, as heat, as thermodynamic work, and as energy associated with matter transfer, and relating them to a function of a body's state, called internal energy.
The Second law of thermodynamics is a physical law of thermodynamics about heat and loss in its conversion.
Third law of thermodynamics states, regarding the properties of closed systems in thermodynamic equilibrium: The entropy of a system approaches a constant value when its temperature approaches absolute zero.