Catalysts lower activation energies equally for forward and backward reactions without altering ∆H
Step 1: Activation energy for the uncatalyzed backward reaction:
\( E_a(\text{backward}) = E_a(\text{forward}) - \Delta H \)
\( E_a(\text{backward}) = 300 - 20 = 280 \, \text{kJ/mol} \)
Step 2: Using the given temperatures and equal rates, calculate \( E_a(\text{forward, catalyzed}) \):
\( \frac{E_a(\text{forward, catalyzed})}{E_a(\text{forward, uncatalyzed})} = \frac{T_c}{T_u} \)
\( \frac{E_a(\text{forward, catalyzed})}{300} = \frac{300}{600} \)
\( E_a(\text{forward, catalyzed}) = 150 \, \text{kJ/mol} \)
Step 3: Calculate \( E_a(\text{backward, catalyzed}) \):
\( E_a(\text{backward, catalyzed}) = E_a(\text{forward, catalyzed}) - \Delta H \)
\( E_a(\text{backward, catalyzed}) = 150 - 20 = 130 \, \text{kJ/mol} \)
Correctly label the speciation diagram below:
Match the following and choose the correct option from the following:
Note: The symbol indicates a stirrer for mixing (not to scale).
Match List-I with List-II.
Choose the correct answer from the options given below :