Question:

For a real gas at 25°C temperature and high pressure (99 bar) the value of the compressibility factor is 2, so the value of van der Waal’s constant ‘b’ should be ______ × 10–2 L mol–1 (Nearest integer).
(Given R=0.083 L bar K-1 mol-1)

Updated On: Sep 24, 2024
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Correct Answer: 25

Solution and Explanation

The correct answer is: 25.

For 1 mole at high pressure
P(V-b) = RT
PV-Pb = RT
\(\frac{PV}{RT}\)= 1+\(\frac{Pb}{RT}\)
Z = 1+\(\frac{Pb}{RT}\)
1 = \(\frac{99(b)}{0.083×298}\)
b = \(\frac{0.083 ×298}{99}\)≈0.249≈25×10-2

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Concepts Used:

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An ideal gas is a theoretical gas composed of a set of randomly-moving point particles that interact only through elastic collisions.

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