For 1 mol of gas, the plot of pV vs. p is shown below. p is the pressure and V is the volume of the gas. What is the value of compressibility factor at point A?
When solving compressibility factor problems:
Start by expressing \(Z = \frac{PV}{RT}\) and substitute the appropriate gas law (e.g., Van der Waals equation).
Expand and simplify using the given conditions to isolate terms involving \(V\), \(a\), and \(b\).
Pay attention to the behavior of \(Z\) in real gas scenarios.
\(1-\frac{a}{RTV}\)
\(1+\frac{b}{V}\)
\(1-\frac{b}{V}\)
\(1+\frac{a}{RTV}\)
For 1 mole of real gas, \[ PV = ZRT \] From the graph, \(PV\) for a real gas is less than \(PV\) for an ideal gas at point A. Thus, \(Z < 1\). The compressibility factor \(Z\) is given by: \[ Z = 1 - \frac{a}{V_m RT} \] Substituting into the definition of \(Z\) and simplifying: \[ Z = 1 - \frac{a}{RTV} \]
A point particle of charge \( Q \) is located at \( P \) along the axis of an electric dipole 1 at a distance \( r \) as shown in the figure. The point \( P \) is also on the equatorial plane of a second electric dipole 2 at a distance \( r \). The dipoles are made of opposite charge \( q \) separated by a distance \( 2a \). For the charge particle at \( P \) not to experience any net force, which of the following correctly describes the situation?


