For 1 mol of gas, the plot of pV vs. p is shown below. p is the pressure and V is the volume of the gas. What is the value of compressibility factor at point A?
When solving compressibility factor problems:
Start by expressing \(Z = \frac{PV}{RT}\) and substitute the appropriate gas law (e.g., Van der Waals equation).
Expand and simplify using the given conditions to isolate terms involving \(V\), \(a\), and \(b\).
Pay attention to the behavior of \(Z\) in real gas scenarios.
\(1-\frac{a}{RTV}\)
\(1+\frac{b}{V}\)
\(1-\frac{b}{V}\)
\(1+\frac{a}{RTV}\)
For 1 mole of real gas, \[ PV = ZRT \] From the graph, \(PV\) for a real gas is less than \(PV\) for an ideal gas at point A. Thus, \(Z < 1\). The compressibility factor \(Z\) is given by: \[ Z = 1 - \frac{a}{V_m RT} \] Substituting into the definition of \(Z\) and simplifying: \[ Z = 1 - \frac{a}{RTV} \]
The molar mass of the water insoluble product formed from the fusion of chromite ore \(FeCr_2\text{O}_4\) with \(Na_2\text{CO}_3\) in presence of \(O_2\) is ....... g mol\(^{-1}\):
0.1 mole of compound S will weigh ...... g, (given the molar mass in g mol\(^{-1}\) C = 12, H = 1, O = 16) 
Among $ 10^{-10} $ g (each) of the following elements, which one will have the highest number of atoms?
Element : Pb, Po, Pr and Pt
0.1 mol of the following given antiviral compound (P) will weigh .........x $ 10^{-1} $ g. 
If all the words with or without meaning made using all the letters of the word "KANPUR" are arranged as in a dictionary, then the word at 440th position in this arrangement is: