To solve the problem, we need to calculate the power of a lens whose focal length is given.
1. Formula for Power of a Lens:
The power \( P \) of a lens in diopters (D) is given by:
\[ P = \frac{100}{f(\text{in cm})} \]
2. Substituting the Given Focal Length:
Given: \( f = 25 \, \text{cm} \)
\[ P = \frac{100}{25} = 4 \, \text{D} \]
Final Answer:
The power of the lens is 4D (Option C).
A current element X is connected across an AC source of emf \(V = V_0\ sin\ 2πνt\). It is found that the voltage leads the current in phase by \(\frac{π}{ 2}\) radian. If element X was replaced by element Y, the voltage lags behind the current in phase by \(\frac{π}{ 2}\) radian.
(I) Identify elements X and Y by drawing phasor diagrams.
(II) Obtain the condition of resonance when both elements X and Y are connected in series to the source and obtain expression for resonant frequency. What is the impedance value in this case?