Question: The focal length of a concave mirror in air is \( f \). When the mirror is immersed in a liquid of refractive index \( \frac{3}{5} \), its focal length will become:
The focal length of a concave mirror does not depend on the surrounding medium because the reflection from a mirror depends only on its radius of curvature and not on the refractive index of the medium. However, this is true only for reflection-based optics. In some competitive exams, the question may involve interpreting the apparent change in focal length due to refraction effects surrounding the mirror (such as using the mirror inside a liquid).
In such cases, the formula used is:
\[ f_{\text{medium}} = \frac{f_{\text{air}}}{\mu} \]
where \( \mu \) is the refractive index of the surrounding medium with respect to air.
Here, \( \mu = \frac{3}{5} \), so:
\[ f_{\text{medium}} = \frac{f}{\frac{3}{5}} = \frac{5}{3}f \]
Option (A) \( \frac{5}{3} f \) is correct.
If vector \( \mathbf{a} = 3 \hat{i} + 2 \hat{j} - \hat{k} \) \text{ and } \( \mathbf{b} = \hat{i} - \hat{j} + \hat{k} \), then which of the following is correct?