Find the value of X in terms of ‘a’. [I.] Arithmetic mean of X and Y is ‘a’ while the geometric mean is also ‘a’.
[II.] $\dfrac{X}{Y} = R$; $X - Y = D$
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When two distinct types of means are equal, it imposes a strong constraint — use it directly.
if the question can be answered with the help of any one statement alone but not by the other statement.
if the question can be answered with the help of either of the statements taken individually.
if the question can be answered with the help of both statements together.
if the question cannot be answered even with the help of both statements together.
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The Correct Option isA
Solution and Explanation
From Statement I:
\[
\text{Arithmetic Mean: } \dfrac{X+Y}{2} = a,\quad \text{Geometric Mean: } \sqrt{XY} = a
\]
Solving these two equations gives unique values of X and Y in terms of 'a'. Hence, this is sufficient.
Statement II gives two equations with two variables but with unknown constants \( R \) and \( D \), which cannot be resolved in terms of ‘a’.