Find the ratio in which the line segment joining A(1, – 5) and B(– 4, 5) is divided by the x-axis. Also find the coordinates of the point of division.
Let the ratio in which the line segment joining A (1, −5) and B (−4, 5) is divided by the x-axis be k:1.
Therefore, the coordinates of the point of division are \((\frac{-4k+1}{k+1},\frac{5k-5}{k+1})\)
We know that the y-coordinate of any point on the x-axis is 0.
Therefore, the x-axis divides it in the ratio 1:1.
Division point = \((\frac{-4(1)+1}{1+1},\frac{5(1)-5}{1+1})=\frac{-4+1}{2},\frac{5-5}{2}=(\frac{-3}{2},0)\)
In the adjoining figure, TP and TQ are tangents drawn to a circle with centre O. If $\angle OPQ = 15^\circ$ and $\angle PTQ = \theta$, then find the value of $\sin 2\theta$. 
What is the angle between the hour and minute hands at 4:30?
आप अदिति / आदित्य हैं। आपकी दादीजी को खेलों में अत्यधिक रुचि है। ओलंपिक खेल-2024 में भारत के प्रदर्शन के बारे में जानकारी देते हुए लगभग 100 शब्दों में पत्र लिखिए।