Find the product of the following pairs of monomials.
(i) 4, 7p
(ii) – 4p, 7p
(iii) – 4p, 7pq
(iv) 4p3, – 3p
(v) 4p, 0
(i) 4, 7p
(ii) – 4p, 7p
(iii) – 4p, 7pq
(iv) 4p3, – 3p
(v) 4p, 0
Solution and Explanation
(i) 4 , 7 p = 4 × 7 × p = 28p
(ii) – 4p × 7p = (-4 × 7 ) × (p × p )= -28p2
(iii) – 4p × 7pq =(-4 × 7 ) (p × pq) = -28p2q
(iv) 4p3 × – 3p = (4 × -3 ) (p3 × p ) = -12p4
(v) 4p × 0 = 0
Top Questions on Multiplying a Monomial by a Monomial
- Complete the following table of products:
First monomial → Second monomial ↓
2x
–5y
3x2
– 4xy
7x 2 y
–9x 2 y 2
2x
4x2
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–5y
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-15x2y
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3x2
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. . .
– 4xy
. . .
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7x 2 y
. . .
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–9x2 y2
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- CBSE Class VIII
- Mathematics
- Multiplying a Monomial by a Monomial
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(i) xy, yz, zx
(ii) a, – a2 , a3
(iii) 2, 4y, 8y2 , 16y3
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Fill in the blanks using the correct form of the verbs in brackets.
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