Find the minimum value of ( z = x + 3y ) under the following constraints:
• x + y ≤ 8
• 3x + 5y ≥ 15
• x ≥ 0, y ≥ 0
Step 1: Convert constraints into a feasible region. Solving for boundary points: - \( x = 0 \Rightarrow y = 8 \)
- \( y = 0 \Rightarrow x = 8 \) For \( 3x + 5y = 15 \): - \( x = 0 \Rightarrow y = 3 \)
- \( y = 0 \Rightarrow x = 5 \)
Step 2: Evaluate \( z \) at extreme points. Using intersection points of constraints: \[ \text{Minimum } z = 3. \]
Minimize Z = 5x + 3y \text{ subject to the constraints} \[ 4x + y \geq 80, \quad x + 5y \geq 115, \quad 3x + 2y \leq 150, \quad x \geq 0, \quad y \geq 0. \]
Solve the following L.P.P. by graphical method:
Maximize:
\[ z = 10x + 25y. \] Subject to: \[ 0 \leq x \leq 3, \quad 0 \leq y \leq 3, \quad x + y \leq 5. \]