Find the minimum value of ( z = x + 3y ) under the following constraints:
• x + y ≤ 8
• 3x + 5y ≥ 15
• x ≥ 0, y ≥ 0
Step 1: Convert constraints into a feasible region. Solving for boundary points: - \( x = 0 \Rightarrow y = 8 \)
- \( y = 0 \Rightarrow x = 8 \) For \( 3x + 5y = 15 \): - \( x = 0 \Rightarrow y = 3 \)
- \( y = 0 \Rightarrow x = 5 \)
Step 2: Evaluate \( z \) at extreme points. Using intersection points of constraints: \[ \text{Minimum } z = 3. \]
Solve the following L.P.P. by graphical method:
Maximize:
\[ z = 10x + 25y. \] Subject to: \[ 0 \leq x \leq 3, \quad 0 \leq y \leq 3, \quad x + y \leq 5. \]
(b) Order of the differential equation: $ 5x^3 \frac{d^3y}{dx^3} - 3\left(\frac{dy}{dx}\right)^2 + \left(\frac{d^2y}{dx^2}\right)^4 + y = 0 $