Question:

Find the function $ f(x_1, x_2, x_3) $ satisfying $ f(x_1, x_2, x_3) = 1 $ at $ x_1 = 1, x_2 = x_3 = 0 $ .

Updated On: Jun 23, 2024
  • $ x_{1}' \cdot x_{2} $
  • $ x_{1} \cdot x_{2}' $
  • $ \left(x_{1} + x_{2} +x_{3}\right)' \cdot x_{2} $
  • $ \left(x_{1}' +x_{3}\right) \cdot x_{3} $
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The Correct Option is B

Solution and Explanation

Given, $x_{1}=1, x_{2}=x_{3}=0$ $x_{1} \cdot x_{2}'=1(0)'=1$
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Concepts Used:

Functions

A function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output. Let A & B be any two non-empty sets, mapping from A to B will be a function only when every element in set A has one end only one image in set B.

Kinds of Functions

The different types of functions are - 

One to One Function: When elements of set A have a separate component of set B, we can determine that it is a one-to-one function. Besides, you can also call it injective.

Many to One Function: As the name suggests, here more than two elements in set A are mapped with one element in set B.

Moreover, if it happens that all the elements in set B have pre-images in set A, it is called an onto function or surjective function.

Also, if a function is both one-to-one and onto function, it is known as a bijective. This means, that all the elements of A are mapped with separate elements in B, and A holds a pre-image of elements of B.

Read More: Relations and Functions