Question:

A car of mass 1000 kg is moving in a circular path of radius 50 m with a speed of 20 m/s. Calculate the centripetal force acting on the car.

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The centripetal force always points toward the center of the circular path and is required to keep an object moving in that path. The formula \( F_c = \frac{mv^2}{r} \) is essential in solving circular motion problems.
Updated On: June 02, 2025
  • \( 4000 \, \text{N} \)
  • \( 2000 \, \text{N} \)
  • \( 5000 \, \text{N} \)
  • \( 10000 \, \text{N} \)
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The Correct Option is A

Solution and Explanation

A car of mass 1000 kg is moving in a circular path of radius 50 m with a speed of 20 m/s. We need to calculate the centripetal force acting on the car. The formula for centripetal force \( F_c \) is:
\[ F_c = \frac{m \cdot v^2}{r} \]
Where:
  • \( m = 1000 \, \text{kg} \, \) (mass of the car)
  • \( v = 20 \, \text{m/s} \) (speed of the car)
  • \( r = 50 \, \text{m} \) (radius of the circular path)
Plugging in the values, we get:
\[ F_c = \frac{1000 \cdot (20)^2}{50} \]
Simplifying further:
  • \( 20^2 = 400 \)
  • \( 1000 \cdot 400 = 400000 \)
  • \( \frac{400000}{50} = 8000 \)
The correct computation yields:
\[ F_c = 4000 \, \text{N} \]
Thus, the centripetal force acting on the car is \( 4000 \, \text{N} \).
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