Question

Find the equivalent capacitance between A and B, where \( C = 16 \, \mu F \). 

• A. 48 \( \mu F \)
• B. 8 \( \mu F \)
• C. 32 \( \mu F \)
• D. 16 \( \mu F \)

Hint:

For complex capacitor networks, break the network into simpler series and parallel combinations, and use the formulas for equivalent capacitance to reduce the network step by step until you obtain the final equivalent capacitance.

Answer 1

The Correct Option is C

In this problem, we have several capacitors in series and parallel. When capacitors are in series, their equivalent capacitance \( C_{\text{eq}} \) is given by: \[ \frac{1}{C_{\text{eq}}} = \frac{1}{C_1} + \frac{1}{C_2} + \dots \] For capacitors in parallel, their equivalent capacitance is the sum of their individual capacitances: \[ C_{\text{eq}} = C_1 + C_2 + \dots \] Given that \( C = 16 \, \mu F \), the capacitors are arranged in a combination of series and parallel. After applying the appropriate formulas, we find the equivalent capacitance between points A and B is \( 32 \, \mu F \).