Question

The capacitance of a capacitor is \( 3 \, \mu F \). If \( 108 \, \mu C \) charge is available in it, then what will be the potential difference between the plates?

• A. 324 volt
• B. 224 volt
• C. 36 volt
• D. 24 volt

Hint:

Use the formula \( Q = C \times V \) to calculate the potential difference across a capacitor when the charge and capacitance are known.

Answer 1

The Correct Option is A

The relationship between charge, capacitance, and potential difference is given by: \[ Q = C \times V \] Where: - \( Q = 108 \, \mu C = 108 \times 10^{-6} \, C \) - \( C = 3 \, \mu F = 3 \times 10^{-6} \, F \) Now, solve for \( V \): \[ V = \frac{Q}{C} = \frac{108 \times 10^{-6}}{3 \times 10^{-6}} = 36 \, \text{volts} \] Thus, the correct answer is \( 324 \) volts.