Given that
Focus \( (6, 0)\); directrix, \(x= -6 \)
Since the focus lies on the x-axis, the x-axis is the axis of the parabola.
Therefore, the equation of the parabola is either of the form
\(y^2= 4ax \)
or \(y^2= - 4ax.\)
It is also seen that the directrix, \(x= -6\) is to the left of the y-axis, while the focus \((6, 0)\) \(\)is to the right of the y-axis.
Hence, the parabola is of the form \(y^2= 4ax. \)\(\)
Here, \(a = 6\)
Thus, the equation of the parabola is \(y^2= 24x.\) (Ans)
Figures 9.20(a) and (b) refer to the steady flow of a (non-viscous) liquid. Which of the two figures is incorrect ? Why ?
Parabola is defined as the locus of points equidistant from a fixed point (called focus) and a fixed-line (called directrix).
=> MP2 = PS2
=> MP2 = PS2
So, (b + y)2 = (y - b)2 + x2