Find the area of the region enclosed by the ellipse \[ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1. \]
Step 1: The area of an ellipse with the equation \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \) is given by the formula: \[ A = \pi a b. \]
Step 2: Here, \( a \) and \( b \) represent the lengths of the semi-major and semi-minor axes of the ellipse, respectively.
Step 3: Therefore, the area enclosed by the ellipse is simply: \[ A = \pi a b. \] Thus, the area of the region enclosed by the ellipse is \( \pi a b \).
Let a line passing through the point $ (4,1,0) $ intersect the line $ L_1: \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} $ at the point $ A(\alpha, \beta, \gamma) $ and the line $ L_2: x - 6 = y = -z + 4 $ at the point $ B(a, b, c) $. Then $ \begin{vmatrix} 1 & 0 & 1 \\ \alpha & \beta & \gamma \\ a & b & c \end{vmatrix} \text{ is equal to} $