
Let the radius of the circle be r.
circumference = 22cm
2πr = 22
r = 2π22 = π11
Quadrant of circle will substend 90°angle at the centre of the circle.
Area of such quadrant of the circle = 360°90°× πr2
= 41× π×(π11)2
= 4π121= 4×22121×7
= 877cm2
Therefore, area of a quadrant of a circle is 877cm2.